A sphere,a cube,and a thin circular plate,all | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The rate of cooling is given by the formula $\frac{d	heta}{dt} = \frac{A \varepsilon \sigma (T^4 - T_0^4)}{mc}$.Since all objects have the same m

Vedclass · Accepted Answer

Plate

Vedclass · Answer

(A) The rate of cooling is given by the formula $\frac{d	heta}{dt} = \frac{A \varepsilon \sigma (T^4 - T_0^4)}{mc}$.Since all objects have the same mass $m$,material (same specific heat $c$),and are at the same initial temperature $T$,the rate of cooling is directly proportional to the surface area $A$ of the object $(\frac{d	heta}{dt} \propto A)$.For a given mass and density,the surface area is largest for a thin circular plate and smallest for a sphere.Therefore,the plate has the largest surface area,which leads to the fastest rate of cooling.Thus,the plate will cool first.

$A$ sphere,a cube,and a thin circular plate,all made of the same material and having the same mass,are initially heated to a temperature of $1000^{\circ}C$. Which one of these will cool first?

Similar Questions

As compared to a person with white skin,a person with black skin will experience:

Two thermometers $A$ and $B$ are exposed to sunlight. The bulb of $A$ is painted black,but that of $B$ is not painted. Which of the following statements is correct regarding this case?

For an opaque body,the coefficient of transmission is:

If the transmission power of a surface is $\frac{1}{9}$ and the reflective power is $\frac{1}{6}$,then what is its absorptive power?

For a perfect black body,the absorption coefficient is

Vedclass Test Series

Exam Paper Generator

Online Exam Module