The temperature gradient in a rod of length 7 | vedclass

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Question

(B) The temperature gradient is defined as the rate of change of temperature with respect to distance,given by $T_g = \frac{T_h - T_c}{L}$,where $T_h$

Vedclass · Accepted Answer

$40$

Vedclass · Answer

(B) The temperature gradient is defined as the rate of change of temperature with respect to distance,given by $T_g = \frac{T_h - T_c}{L}$,where $T_h$ is the temperature of the hotter end,$T_c$ is the temperature of the cooler end,and $L$ is the length of the rod.Given:Length $L = 75 \ cm = 0.75 \ m$Temperature gradient $T_g = 40^{\circ} C/m$Cooler end temperature $T_c = 10^{\circ} C$Substituting the values into the formula:$40 = \frac{T_h - 10}{0.75}$$T_h - 10 = 40 	imes 0.75$$T_h - 10 = 30$$T_h = 30 + 10 = 40^{\circ} C$Therefore,the temperature of the hotter end is $40^{\circ} C$.

The temperature gradient in a rod of length $75 \ cm$ is $40^{\circ} C/m$. If the temperature of the cooler end of the rod is $10^{\circ} C$,then the temperature of the hotter end is: (in $^{\circ} C$)

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