The system of the wedge and the block connect | vedclass

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(B) Since the wedge is fixed,we can apply the principle of conservation of mechanical energy for the block of mass $M$.Let $x_m$ be the maximum elonga

Vedclass · Accepted Answer

$\frac{6Mg}{5k}$

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(B) Since the wedge is fixed,we can apply the principle of conservation of mechanical energy for the block of mass $M$.Let $x_m$ be the maximum elongation in the spring.At maximum elongation,the velocity of the block is zero.The loss in gravitational potential energy of the block is equal to the gain in elastic potential energy of the spring.$M g (x_m \sin 	heta) = \frac{1}{2} k x_m^2$Solving for $x_m$:$x_m = \frac{2 M g \sin 	heta}{k}$Given $	heta = 37^\circ$,we know $\sin 37^\circ = \frac{3}{5}$.Substituting the value of $\sin 37^\circ$:$x_m = \frac{2 M g (3/5)}{k} = \frac{6 M g}{5 k}$

The system of the wedge and the block connected by a massless spring as shown in the figure is released with the spring in its natural length. Friction is absent. The maximum elongation in the spring will be:

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