The surface tension of a liquid is 0.5 , N/m. | vedclass

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(B) The surface energy $U$ of a liquid film is given by the formula $U = T 	imes \Delta A$,where $T$ is the surface tension and $\Delta A$ is the tot

Vedclass · Accepted Answer

$2.0 	imes 10^{-2} \, J$

Vedclass · Answer

(B) The surface energy $U$ of a liquid film is given by the formula $U = T 	imes \Delta A$,where $T$ is the surface tension and $\Delta A$ is the total change in surface area.Since a film has two surfaces (top and bottom),the total area $\Delta A = 2 	imes A$,where $A$ is the area of the ring.Given: $T = 0.5 \, N/m$ and $A = 0.02 \, m^2$.Therefore,$\Delta A = 2 	imes 0.02 = 0.04 \, m^2$.Surface energy $U = 0.5 	imes 0.04 = 0.02 \, J$.This can be written as $2.0 	imes 10^{-2} \, J$.

The surface tension of a liquid is $0.5 \, N/m$. If a film is held on a ring of area $0.02 \, m^2$,its surface energy is:

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