The sum of the digits in the unit's place of | vedclass

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(B) To form a $4-$digit number using the digits $3, 4, 5,$ and $6$ without repetition,we have $4! = 24$ total numbers.If we fix one digit at the unit'

Vedclass · Accepted Answer

$108$

Vedclass · Answer

(B) To form a $4-$digit number using the digits $3, 4, 5,$ and $6$ without repetition,we have $4! = 24$ total numbers.If we fix one digit at the unit's place,the remaining $3$ positions can be filled by the remaining $3$ digits in $3! = 6$ ways.Therefore,each digit ($3, 4, 5,$ and $6$) appears in the unit's place exactly $6$ times.The sum of the digits in the unit's place is calculated as:Sum $= (6 	imes 3) + (6 	imes 4) + (6 	imes 5) + (6 	imes 6)$Sum $= 6 	imes (3 + 4 + 5 + 6)$Sum $= 6 	imes 18$Sum $= 108$

The sum of the digits in the unit's place of all the $4-$digit numbers formed by using the digits $3, 4, 5,$ and $6$,without repetition,is

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