The sum of squares of two numbers is 90 and t | vedclass

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Question

(A) Let the two numbers be $x$ and $y$.According to the problem:$x^{2} + y^{2} = 90$ $.....(1)$$(x - y)^{2} = 46$ $.....(2)$We know that $(x - y)^{2}

Vedclass · Accepted Answer

$22$

Vedclass · Answer

(A) Let the two numbers be $x$ and $y$.According to the problem:$x^{2} + y^{2} = 90$ $.....(1)$$(x - y)^{2} = 46$ $.....(2)$We know that $(x - y)^{2} = x^{2} + y^{2} - 2xy$.Substituting the values from equation $(1)$ and $(2)$ into the identity:$46 = 90 - 2xy$Rearranging the terms to solve for $xy$:$2xy = 90 - 46$$2xy = 44$$xy = 22$Therefore,the product of the two numbers is $22$.

The sum of squares of two numbers is $90$ and the square of their difference is $46$. The product of the two numbers is

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