The sum of five consecutive integers is $a$ and the sum of next five consecutive integers is $b$. Then $\frac{(b-a)}{100}$ is equal to
The sum of five consecutive integers is $a$ and the sum of next five consecutive integers is $b$. Then $\frac{(b-a)}{100}$ is equal to
- A
$\frac{1}{4}$
- B
$\frac{1}{2}$
- C
$3$
- D
$2$
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