A man whose bowling average is 12.4 takes 5 w | vedclass

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Question

(A) Let the number of wickets taken before the last match be $x$.Total runs conceded before the last match $= 12.4x$.In the last match,he took $5$ wic

Vedclass · Accepted Answer

$85$

Vedclass · Answer

(A) Let the number of wickets taken before the last match be $x$.Total runs conceded before the last match $= 12.4x$.In the last match,he took $5$ wickets for $26$ runs.Total wickets after the last match $= x + 5$.Total runs after the last match $= 12.4x + 26$.The new average is $12.4 - 0.4 = 12.0$.According to the problem,the new average is given by $\frac{12.4x + 26}{x + 5} = 12$.Multiplying both sides by $(x + 5)$,we get $12.4x + 26 = 12(x + 5)$.$12.4x + 26 = 12x + 60$.$12.4x - 12x = 60 - 26$.$0.4x = 34$.$x = \frac{34}{0.4} = \frac{340}{4} = 85$.Therefore,the number of wickets taken before the last match is $85$.

$A$ man whose bowling average is $12.4$ takes $5$ wickets for $26$ runs and,thereby,decreases his average by $0.4$. The number of wickets taken by him before his last match is:

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