The sum of the first $n$ terms of the series $1^2 + 2 \cdot 2^2 + 3^2 + 2 \cdot 4^2 + 5^2 + 2 \cdot 6^2 + \dots$ is $\frac{n(n + 1)^2}{2}$ when $n$ is even. When $n$ is odd,the sum is:

  • A
    $\frac{n(n + 1)^2}{2}$
  • B
    $\frac{1}{2}n^2(n + 1)$
  • C
    $n(n + 1)^2$
  • D
    None of these

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