The sum of the first 20 terms of the A.P. 5, | vedclass

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Question

(A) Given the $A.P.$ is $5, 11, 17, 23, \ldots$Here,the first term $a = 5$.The common difference $d = 11 - 5 = 6$.The number of terms $n = 20$.The for

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$1240$

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(A) Given the $A.P.$ is $5, 11, 17, 23, \ldots$Here,the first term $a = 5$.The common difference $d = 11 - 5 = 6$.The number of terms $n = 20$.The formula for the sum of the first $n$ terms of an $A.P.$ is $S_n = \frac{n}{2} [2a + (n - 1)d]$.Substituting the values: $S_{20} = \frac{20}{2} [2(5) + (20 - 1)6]$.$S_{20} = 10 [10 + (19 	imes 6)]$.$S_{20} = 10 [10 + 114]$.$S_{20} = 10 [124] = 1240$.

The sum of the first $20$ terms of the $A.P.$ $5, 11, 17, 23, \ldots$ is:

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