The structural formula of a compound is CH_3 | vedclass

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(A) The hybridization of a carbon atom is determined by the number of $\pi$ bonds attached to it.$1$. The first carbon $(CH_3-)$ is bonded to $3$ hydr

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$sp^3, sp^2, sp, sp^2$

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(A) The hybridization of a carbon atom is determined by the number of $\pi$ bonds attached to it.$1$. The first carbon $(CH_3-)$ is bonded to $3$ hydrogens and $1$ carbon via single bonds ($4$ $\sigma$ bonds),so it is $sp^3$ hybridized.$2$. The second carbon $(-CH=)$ is bonded to $1$ hydrogen,$1$ single bond,and $1$ double bond ($1$ $\pi$ bond),so it is $sp^2$ hybridized.$3$. The third carbon $(=C=)$ is bonded to two double bonds ($2$ $\pi$ bonds),so it is $sp$ hybridized.$4$. The fourth carbon $(=CH_2)$ is bonded to $2$ hydrogens and $1$ double bond ($1$ $\pi$ bond),so it is $sp^2$ hybridized.Therefore,the hybridization order from left to right is $sp^3, sp^2, sp, sp^2$.

The structural formula of a compound is $CH_3 - CH = C = CH_2$. The type of hybridization at the four carbons from left to right are

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