In the organic compound CH_2=CH-CH_2-CH_2-Ceq | vedclass

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(D) The structure of the compound is $\overset{6}{C}H_2 = \overset{5}{C}H - \overset{4}{C}H_2 - \overset{3}{C}H_2 - \overset{2}{C} \equiv \overset{1}{

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$sp-sp^3$

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(D) The structure of the compound is $\overset{6}{C}H_2 = \overset{5}{C}H - \overset{4}{C}H_2 - \overset{3}{C}H_2 - \overset{2}{C} \equiv \overset{1}{C}H$. Assigning hybridization to each carbon atom: $C_1$ is $sp$ hybridized. $C_2$ is $sp$ hybridized. $C_3$ is $sp^3$ hybridized. $C_4$ is $sp^3$ hybridized. $C_5$ is $sp^2$ hybridized. $C_6$ is $sp^2$ hybridized. The $C_2-C_3$ bond is formed by the overlap of an $sp$ hybridized orbital of $C_2$ and an $sp^3$ hybridized orbital of $C_3$. Therefore,the pair of hybridized orbitals is $sp-sp^3$.

In the organic compound $CH_2=CH-CH_2-CH_2-C\equiv CH$,the pair of hybridized orbitals involved in the formation of the $C_2-C_3$ bond is:

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