The statement p → (p leftrightarrow&nbsp | vedclass

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Question

Here statements $p &rarr; (p \leftrightarrow q)$ and $(q &rarr; p) &rarr; (p &rarr; q) $ both are false only when $p$ is true and $q$ is false ot

Vedclass · Accepted Answer

$(q&rarr; p) &rarr; (p &rarr; q)$

Vedclass · Answer

Here statements $p &rarr; (p \leftrightarrow q)$ and $(q &rarr; p) &rarr; (p &rarr; q) $ both are false only when $p$ is true and $q$ is false otherwise they are true.

The statement $p → (p \leftrightarrow q)$ is logically equivalent to :-

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Consider

Statement $-1 :$$\left( {p \wedge \sim q} \right) \wedge \left( { \sim p \wedge q} \right)$ is a fallacy.

Statement $-2 :$$(p \rightarrow q) \leftrightarrow ( \sim q \rightarrow \sim p )$ is a tautology.