The spectral series observed for the hydrogen atom found in the visible region is

The wavelength of the first line of the Balmer series of a hydrogen atom is $\lambda \ \mathring{A}$. The wavelength of the same line for a doubly ionized lithium atom $(Z = 3)$ is:

$A$ hydrogen atom is excited from the ground state to the energy level $n = 3$. According to Bohr's model,the number of spectral lines emitted is:

Which of the following spectral series of the hydrogen atom lies in the visible range of the electromagnetic spectrum?

The shortest wavelength in the Lyman series of the hydrogen spectrum is $912 \ \mathring{A}$,corresponding to a photon energy of $13.6 \ eV$. The shortest wavelength in the Balmer series is about..... $\mathring{A}$.

In an $H$-like atom,when an electron transits from energy state $n=5$ to $n=2$,a photon of wavelength $434 \, nm$ is emitted. What will be the wavelength of the photon emitted when the transition occurs from energy state $n=4$ to $n=2$?