The spectral emissive power $E_\lambda$ for a body at temperature $T_1$ is plotted against the wavelength and the area under the curve is found to be $A$. At a different temperature $T_2$,the area is found to be $9A$. Then $\lambda_1/\lambda_2 =$

  • A
    $3$
  • B
    $1/3$
  • C
    $1/\sqrt{3}$
  • D
    $\sqrt{3}$

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