The solubility of $CuBr$ is $2 \times 10^{-4} \ mol/L$ at $25 \ ^\circ C$. The $K_{sp}$ value for $CuBr$ is
- A$4 \times 10^{-8} \ mol^2 \ L^{-2}$
- B$4 \times 10^{-11} \ mol^2 \ L^{-2}$
- C$4 \times 10^{-4} \ mol^2 \ L^{-2}$
- D$4 \times 10^{-15} \ mol^2 \ L^{-2}$
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