$A$ solution of $0.01 \ M$ $MgCl_2$ will form a precipitate of $Mg(OH)_2$ at a limiting $pH$ of: (Given: $K_{sp}$ of $Mg(OH)_2 = 1 \times 10^{-12}$)

  • A
    $9$
  • B
    $5$
  • C
    $12$
  • D
    $2$

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