The solubility of N_2 in water at 300 K and | vedclass

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(D) According to Henry's law,the solubility $(S)$ of a gas is directly proportional to its partial pressure $(P)$: $S \propto P$ or $S = kP$. Given: $

Vedclass · Accepted Answer

$0.015$

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(D) According to Henry's law,the solubility $(S)$ of a gas is directly proportional to its partial pressure $(P)$: $S \propto P$ or $S = kP$. Given: $P_1 = 500 \ torr$,$S_1 = 0.01 \ g \ L^{-1}$,$P_2 = 750 \ torr$. Using the relation $\frac{S_1}{S_2} = \frac{P_1}{P_2}$: $\frac{0.01}{S_2} = \frac{500}{750}$ $S_2 = \frac{0.01 	imes 750}{500} = 0.015 \ g \ L^{-1}$.

The solubility of $N_2$ in water at $300 \ K$ and $500 \ torr$ partial pressure is $0.01 \ g \ L^{-1}$. The solubility (in $g \ L^{-1}$) at $750 \ torr$ partial pressure is

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