Calculate the solubility of a gas in water at $0.8 \ atm$ and $25^{\circ} C$. [Henry's law constant is $6.85 \times 10^{-4} \ mol \ dm^{-3} \ atm^{-1}$]

  • A
    $5.48 \times 10^{-4} \ mol \ dm^{-3}$
  • B
    $3.94 \times 10^{-4} \ mol \ dm^{-3}$
  • C
    $6.858 \times 10^{-4} \ mol \ dm^{-3}$
  • D
    $2.74 \times 10^{-4} \ mol \ dm^{-3}$

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