The shortest distance between the skew-lines $\frac{x-3}{-1}=\frac{y-4}{2}=\frac{z+2}{1}$ and $\frac{x-1}{1}=\frac{y+7}{3}=\frac{z+2}{2}$ is

  • A
    $6$
  • B
    $7$
  • C
    $3 \sqrt{3}$
  • D
    $\sqrt{35}$

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