The shape of AsF_5 according to VSEPR theory | vedclass

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(B) To determine the shape of $AsF_5$ using $VSEPR$ theory,we first calculate the number of valence electrons on the central atom $As$.$As$ belongs to

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Trigonal bipyramidal

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(B) To determine the shape of $AsF_5$ using $VSEPR$ theory,we first calculate the number of valence electrons on the central atom $As$.$As$ belongs to group $15$,so it has $5$ valence electrons.It forms $5$ bonds with $5$ $F$ atoms.Number of electron pairs $= \frac{1}{2} 	imes (V + M - C + A) = \frac{1}{2} 	imes (5 + 5 - 0 + 0) = 5$.Since there are $5$ bond pairs and $0$ lone pairs,the hybridization is $sp^3d$.$A$ molecule with $5$ bond pairs and $0$ lone pairs adopts a trigonal bipyramidal geometry.

The shape of $AsF_5$ according to $VSEPR$ theory $:-$

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