According to $VSEPR$ theory,the most probable shape of the molecule having $4$ electron pairs in the outer shell of the central atom is

Which of the following species are isostructural: $NO^{-}_3, CO^{2-}_3, ClO^{-}_3,$ and $SO_3$?

Among the following species, the $H - X - H$ bond angle $(X = B, N, \text{ or } P)$ follows the order:

Given below are two statements:
Statement $I$: The number of compounds among $SO_2$,$SO_3$,$SF_4$,$SF_6$ and $H_2S$ in which sulphur does not obey the Octet rule is $3$.
Statement $II$: Among $[H_2O, ClF_3, SF_4]$,$[NH_3, BrF_5, SF_4]$,$[BrF_5, ClF_3, XeF_4]$ and $[XeF_4, ClF_3, H_2O]$,the number of sets in which all the molecules have one lone pair of electrons on the central atom is $1$.

Given below are two statements:
Statement $(I) :$ For $ClF_3$,all three possible structures may be drawn as follows:
(Image provided)
Statement $(II) :$ Structure $III$ is most stable,as the orbitals having the lone pairs are axial,where the $\ell p-bp$ repulsion is minimum.
In the light of the above statements,choose the most appropriate answer from the options given below:

Molecular bromine on reaction with three moles of molecular fluorine produces an interhalogen compound. The total number of lone pairs at the central halogen atom is