The shape of XeO_2F_2 molecule is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The central atom $Xe$ has $8$ valence electrons.It forms $2$ double bonds with $O$ atoms and $2$ single bonds with $F$ atoms,utilizing $6$ electro

Vedclass · Accepted Answer

see-saw

Vedclass · Answer

(D) The central atom $Xe$ has $8$ valence electrons.It forms $2$ double bonds with $O$ atoms and $2$ single bonds with $F$ atoms,utilizing $6$ electrons.This leaves $1$ lone pair on the $Xe$ atom.The total number of electron pairs around $Xe$ is $4$ (bonding pairs) $+ 1$ (lone pair) $= 5$.According to $VSEPR$ theory,$5$ electron pairs correspond to a trigonal bipyramidal electron geometry.With one lone pair occupying an equatorial position,the molecular shape is see-saw.

The shape of $XeO_2F_2$ molecule is

Similar Questions

$BF_3$ is used as a catalyst in several industrial processes due to its

The sum of lone pairs present on the central atom of the interhalogen $IF_5$ and $IF_7$ is $.........$.

Which of the following pairs has the same structure?

What are the structures and shapes of $SF_4$ and $ClF_3$?

In which of the following pairs,the central atoms have the same number of lone pairs of electrons?

Vedclass Test Series

Exam Paper Generator

Online Exam Module