In which of the following pairs,the central a | vedclass

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(B) To determine the number of lone pairs on the central atom,we use the formula: $	ext{Lone pairs} = \frac{1}{2} (V - N - C)$,where $V$ is the numbe

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$XeF_2, ICl_2^{-}$

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(B) To determine the number of lone pairs on the central atom,we use the formula: $	ext{Lone pairs} = \frac{1}{2} (V - N - C)$,where $V$ is the number of valence electrons of the central atom,$N$ is the number of monovalent atoms bonded to it,and $C$ is the charge on the species.$1$. For $XeF_2$: $V=8, N=2, C=0$. $	ext{Lone pairs} = \frac{1}{2}(8-2) = 3$.$2$. For $ICl_2^{-}$: $V=7, N=2, C=1$. $	ext{Lone pairs} = \frac{1}{2}(7-2+1) = 3$.Both $XeF_2$ and $ICl_2^{-}$ have $3$ lone pairs on their respective central atoms.

In which of the following pairs,the central atoms have the same number of lone pairs of electrons?

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