The series of positive multiples of $3$ is divided into sets: $\{3\}, \{6, 9, 12\}, \{15, 18, 21, 24, 27\}, \ldots$. Then the sum of the elements in the $11^{\text{th}}$ set is equal to $................$

  • A
    $6994$
  • B
    $6698$
  • C
    $6695$
  • D
    $6993$

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