The sensitivity of a galvanometer is $60 \text{ div/A}$. When a shunt is used,its sensitivity becomes $10 \text{ div/A}$. If the resistance of the galvanometer is $20 \ \Omega$,then the value of the shunt used is: (in $Omega$)

  • A
    $4$
  • B
    $5$
  • C
    $20$
  • D
    $2$

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