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(C) Visible light corresponds to the wavelength range of approximately $380 \, nm$ to $750 \, nm$. Using the relation $E = \frac{hc}{\lambda}$, where

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$1.8$

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(C) Visible light corresponds to the wavelength range of approximately $380 \, nm$ to $750 \, nm$. Using the relation $E = \frac{hc}{\lambda}$, where $h = 6.63 	imes 10^{-34} \, J \cdot s$, $c = 3 	imes 10^8 \, m/s$, and $1 \, eV = 1.6 	imes 10^{-19} \, J$. For the longest wavelength of visible light $(\lambda = 750 \, nm)$, the energy is $E = \frac{1240 \, eV \cdot nm}{750 \, nm} \approx 1.65 \, eV$. In practice, to emit visible light efficiently, the semiconductor material used for the fabrication of visible LEDs must have a band gap of at least $1.8 \, eV$.

The semiconductor used for the fabrication of visible LEDs must at least have a band gap of (in $eV$)

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