The self-inductance of a long solenoid of cro | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The magnetic field $B$ inside a long solenoid is given by $B = \mu_0 n I$,where $n$ is the number of turns per unit length and $I$ is the current.

Vedclass · Accepted Answer

$\mu_0 n^2 Al$

Vedclass · Answer

(B) The magnetic field $B$ inside a long solenoid is given by $B = \mu_0 n I$,where $n$ is the number of turns per unit length and $I$ is the current.The magnetic flux $\phi$ through a single turn of the solenoid is $\phi = B \cdot A = \mu_0 n I A$.The total number of turns $N$ in a solenoid of length $l$ is $N = n \cdot l$.The total magnetic flux linkage $\Phi$ is given by $\Phi = N \cdot \phi = (nl) \cdot (\mu_0 n I A) = \mu_0 n^2 I A l$.By definition,the self-inductance $L$ is given by $\Phi = L I$,so $L = \frac{\Phi}{I} = \mu_0 n^2 A l$.

The self-inductance of a long solenoid of cross-sectional area $A$,length $l$ and $n$ turns per unit length is given by

Similar Questions

$A$ circuit has self-inductance $L$ and carries a current $I$. To prevent sparking when the circuit is switched off,a capacitor which can withstand potential difference $V$ is used. The least capacitance is

If in a coil the rate of change of area is $5 \, m^2/ms$ and the current changes from $2 \, A$ to $1 \, A$ in $2 \times 10^{-3} \, s$. If the magnetic field is $1 \, T$,then the self-inductance of the coil is......$H$

Consider a current in a circuit falls from $6.0 \,A$ to $1.0 \,A$ in $0.2 \,s$. If an average emf of $150 \,V$ is induced by the circuit,then the self inductance of the circuit is (in $\,H$)

In the given circuit, if $\frac{dI}{dt} = -1 \, A/s$, then the value of $(V_A - V_B)$ at this instance will be (in $\, V$)

$A$ magnetic flux of $5 \mu Wb$ is linked with a coil when a current of $1 \ mA$ flows through it. Calculate the self inductance of the coil.

Vedclass Test Series

Exam Paper Generator

Online Exam Module