The self-inductance of a coil is $50 mH$. When a current of $1 A$ passing through the coil reduces to zero at a steady rate in $0.1 s$,find the self-induced emf. (in $V$)

When a current $i$ through a solenoid is increasing at a constant rate, then the induced current is

$A$ solenoid of radius $R$ has $n$ turns per unit length. The self-inductance of the solenoid per unit length is:

When a current of $1 \,A$ is passed through a coil of $100$ turns, the flux associated with it is $2.5 \times 10^{-5} \,Wb/\text{turn}$. The self-inductance of the coil in millihenry is:

$A$ coil has $N$ turns and the current passing through it is $I$ ampere,resulting in a self-inductance of $L$ Henry. If the current changes to $5I$ $A$,the new self-inductance will be . . . . . . $H$.

If the number of turns per unit length in a solenoid is tripled,the self-inductance of the solenoid will