$A$ coil has $N$ turns and the current passing through it is $I$ ampere,resulting in a self-inductance of $L$ Henry. If the current changes to $5I$ $A$,the new self-inductance will be . . . . . . $H$.

  • A
    $5L$
  • B
    $\frac{1}{5}L$
  • C
    $25L$
  • D
    $L$

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