The roots of the equation $ix^2 - 4x - 4i = 0$ are
- A$-2i$
- B$2i$
- C$-2i, -2i$
- D$2i, 2i$
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Similar Questions
Let $a, b, c \in R$ and $\alpha, \beta$ be the real roots of the equation $ax^2 + bx + c = 0$. If $a < 0, b > 0, c > 0$ and $\alpha < \beta$,then:
Difficult
View SolutionSolve the given two equations and select the correct answer from the given options.
$I.$ $\sqrt{x} - \frac{(18)^{15/2}}{x^2} = 0$
$II.$ $\sqrt{y} = \frac{(19)^{9/2}}{y}$
$I.$ $\sqrt{x} - \frac{(18)^{15/2}}{x^2} = 0$
$II.$ $\sqrt{y} = \frac{(19)^{9/2}}{y}$
Difficult
View SolutionSolve the given two equations and select the correct answer from the given options.
$I. \quad x - 7\sqrt{x} + 12 = 0$
$II. \quad y - 5\sqrt{y} + 6 = 0$
$I. \quad x - 7\sqrt{x} + 12 = 0$
$II. \quad y - 5\sqrt{y} + 6 = 0$
Difficult
View SolutionSolve the given two equations and select the correct answer from the given options.
$I.$ $16 x^{2}+20 x+6=0$
$II.$ $10 y^{2}+38 y+24=0$
$I.$ $16 x^{2}+20 x+6=0$
$II.$ $10 y^{2}+38 y+24=0$
Difficult
View SolutionSolve the given two equations and select the correct answer from the given options.
$I.$ $x = \sqrt{2304}$
$II.$ $y^2 = 2304$
$I.$ $x = \sqrt{2304}$
$II.$ $y^2 = 2304$
Medium
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