The roots of the quadratic equation x^{2}-2x- | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To find the roots of the quadratic equation $x^{2}-2x-15=0$,we can use the factorization method.We need to find two numbers whose product is $-15$

Vedclass · Accepted Answer

$5$ and $-3$

Vedclass · Answer

(A) To find the roots of the quadratic equation $x^{2}-2x-15=0$,we can use the factorization method.We need to find two numbers whose product is $-15$ and whose sum is $-2$.These two numbers are $-5$ and $3$,since $(-5) 	imes 3 = -15$ and $(-5) + 3 = -2$.Now,rewrite the equation as: $x^{2}-5x+3x-15=0$.Factor by grouping: $x(x-5)+3(x-5)=0$.This gives: $(x-5)(x+3)=0$.Setting each factor to zero,we get $x-5=0$ or $x+3=0$.Therefore,$x=5$ or $x=-3$.The roots of the equation are $5$ and $-3$.

The roots of the quadratic equation $x^{2}-2x-15=0$ are ....... .

Similar Questions

Obtain the roots of the following quadratic equation by using the general formula for the solution: $2x^{2} - 2\sqrt{2}x + 1 = 0$.

Check whether the equation $6x^2 - 7x + 2 = 0$ has real roots, and if it has, find them by the method of completing the squares.

We get $2$ litres of kerosene less in Rs. $360$ if the price of kerosene increases by Rs. $2$ per litre. Find the original price of kerosene per litre.

In Hindu civilization,$\ldots \ldots \ldots$ gave the method to solve quadratic equations.

Examine whether the following equation is quadratic or not: $(x-2)^{2}+1=2x-3$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module