The resonant frequency of a series LCR circui | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) At resonance frequency $f_R$, the inductive reactance $X_L$ equals the capacitive reactance $X_C$, so $X_L = X_C = X_0$.When the frequency is doub

Vedclass · Accepted Answer

$\frac{1}{4} X_{L_1}$

Vedclass · Answer

(B) At resonance frequency $f_R$, the inductive reactance $X_L$ equals the capacitive reactance $X_C$, so $X_L = X_C = X_0$.When the frequency is doubled to $f' = 2 f_R$, the new inductive reactance is $X_{L_1} = 2 \pi (2 f_R) L = 2 X_L = 2 X_0$.The new capacitive reactance is $X_{C_1} = \frac{1}{2 \pi (2 f_R) C} = \frac{1}{2} X_C = \frac{1}{2} X_0$.From $X_{L_1} = 2 X_0$, we have $X_0 = \frac{X_{L_1}}{2}$.Substituting this into the expression for $X_{C_1}$, we get $X_{C_1} = \frac{1}{2} \left( \frac{X_{L_1}}{2} \right) = \frac{X_{L_1}}{4}$.

The resonant frequency of a series $LCR$ circuit is $f_R$. The circuit is connected to a sinusoidally alternating e.m.f. of frequency $2 f_R$. The inductive reactance becomes $X_{L_1}$ and capacitive reactance becomes $X_{C_1}$ after changing the frequency. $X_{C_1}$ is equal to:

Similar Questions

In an $LCR$ circuit having $L = 8.0 \, H$,$C = 0.5 \, \mu F$,and $R = 100 \, \Omega$ in series,the resonance frequency in radians per second is:

What is the value of inductance $L$ in $mH$ for which the current is maximum in a series $LCR$ circuit with $C = 10 \, \mu F$ and $\omega = 1000 \, rad/sec$?

The $Q$-factor of a resonant circuit is equal to

The reading of the ammeter in the circuit shown will be: (in $A$)

In an $LCR$ circuit,at resonance

Vedclass Test Series

Exam Paper Generator

Online Exam Module