The resistance of a galvanometer is $50\,\Omega$ and the current required to give full-scale deflection is $100\,\mu A$. In order to convert it into an ammeter reading up to $10\,A$,it is necessary to put a resistance of

  • A
    $5 \times 10^{-3}\,\Omega$ in parallel
  • B
    $5 \times 10^{-4}\,\Omega$ in parallel
  • C
    $10^5\,\Omega$ in series
  • D
    $99,950\,\Omega$ in series

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Similar Questions

$A$ $50\,\Omega$ resistance is connected to a battery of $5\,V$. $A$ galvanometer of resistance $100\,\Omega$ is to be used as an ammeter to measure current through the resistance. For this,a resistance $r_s$ is connected to the galvanometer. Which of the following connections should be employed if the measured current is within $1\%$ of the current without the ammeter in the circuit?

Give the uses of a galvanometer.

$A$ galvanometer of resistance $50 \Omega$ gives a full-scale deflection for a current of $5 \times 10^{-4} \text{ A}$. The resistance that should be connected in series with the galvanometer to read $3 \text{ V}$ is: (in $Omega$)

$A$ moving coil galvanometer is converted into an ammeter reading up to $0.03\,A$ by connecting a shunt of resistance $4r$ across it,and into an ammeter reading up to $0.06\,A$ when a shunt of resistance $r$ is connected across it. What is the maximum current which can be sent through this galvanometer if no shunt is used?

Give the difference between an Ammeter and a Voltmeter.

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