The relation between frequency '$n$',wavelength '$\lambda$',and velocity of propagation '$v$' of a wave is:

$A$ sound wave of frequency $200 Hz$ is travelling in air. The speed of sound in the air is $340 m s^{-1}$. What is the phase difference at a given instant between two points separated by a distance of $85 cm$ along the direction of propagation?

$A$ transverse wave is described by the equation $Y = Y_0 \sin 2\pi \left( ft - \frac{x}{\lambda} \right)$. The maximum particle velocity is four times the wave velocity if:

$A$ wave is given by $y = 3 \sin 2\pi \left( \frac{t}{0.04} - \frac{x}{0.01} \right)$,where $y$ is in $cm$. The frequency of the wave and the maximum acceleration of the particle are:

The equation of a travelling wave is $y = a \sin 2 \pi (p t - \frac{x}{5})$. Then the ratio of the maximum particle velocity to the wave velocity is ...........

Obtain the relation between wave velocity,angular frequency,and angular wave number.