A sound wave of frequency 200 Hz is travellin | vedclass

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(A) Given: Frequency $f = 200 Hz$,Speed $v = 340 m s^{-1}$,Distance $\Delta x = 85 cm = 0.85 m$. First,calculate the wavelength $\lambda$ using the fo

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$\pi$

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(A) Given: Frequency $f = 200 Hz$,Speed $v = 340 m s^{-1}$,Distance $\Delta x = 85 cm = 0.85 m$. First,calculate the wavelength $\lambda$ using the formula $\lambda = \frac{v}{f}$. $\lambda = \frac{340}{200} = 1.7 m$. The phase difference $\Delta \phi$ is related to the path difference $\Delta x$ by the formula $\Delta \phi = \frac{2 \pi}{\lambda} 	imes \Delta x$. Substituting the values: $\Delta \phi = \frac{2 \pi}{1.7} 	imes 0.85$. $\Delta \phi = \frac{2 \pi}{1.7} 	imes \frac{1.7}{2} = \pi$ radians.

$A$ sound wave of frequency $200 Hz$ is travelling in air. The speed of sound in the air is $340 m s^{-1}$. What is the phase difference at a given instant between two points separated by a distance of $85 cm$ along the direction of propagation?

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