The relation between $Z_E, H_E$,and $B_E$ is . . . . . . .

  • A
    $B_E = \sqrt{Z_E^2 + H_E^2}$
  • B
    $B_E = Z_E \cdot H_E$
  • C
    $B_E = \frac{Z_E}{H_E}$
  • D
    $B_E = \frac{H_E}{Z_E}$

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Similar Questions

Magnetic meridian is a

Assume the dipole model for Earth's magnetic field $B$,which is given by:
$B_v = \text{vertical component of magnetic field} = \frac{\mu_0}{4\pi} \frac{2m \cos \theta}{r^3}$
$B_H = \text{horizontal component of magnetic field} = \frac{\mu_0}{4\pi} \frac{m \sin \theta}{r^3}$
where $\theta = 90^{\circ} - \text{latitude}$ as measured from the magnetic equator.
$(a)$ Find the loci of points for which the dip angle is $\pm 45^{\circ}$.

$A$ dip needle in a plane perpendicular to the magnetic meridian will remain:

Give the location of magnetic:
$(i)$ north pole
$(ii)$ south pole

If the angles of dip at two places are $30^{\circ}$ and $45^{\circ}$ respectively,then the ratio of horizontal components of earth's magnetic field at the two places will be

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