The region represented by the inequation x-y | vedclass

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(C) The given system of inequalities is:$x - y \leq -1$ $(1)$$x - y \geq 0$ $(2)$$x \geq 0, y \geq 0$ $(3)$From inequality $(1)$,we have $x - y \leq -

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does not exist

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(C) The given system of inequalities is:$x - y \leq -1$ $(1)$$x - y \geq 0$ $(2)$$x \geq 0, y \geq 0$ $(3)$From inequality $(1)$,we have $x - y \leq -1$,which implies $y \geq x + 1$.From inequality $(2)$,we have $x - y \geq 0$,which implies $y \leq x$.Combining these,we get $x + 1 \leq y \leq x$.This implies $x + 1 \leq x$,which simplifies to $1 \leq 0$.Since $1 \leq 0$ is a false statement,there is no value of $x$ and $y$ that can satisfy both inequalities simultaneously.Therefore,the region represented by these inequalities does not exist.

The region represented by the inequation $x-y \leq -1, x-y \geq 0, x \geq 0, y \geq 0$ is $.....$

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