The region between y = 0 and y = d contains a | vedclass

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Question

$\overrightarrow{\mathrm{B}}=\mathrm{B} \hat{\mathrm{k}}$

$r=\frac{m v}{q B}$

$r=2 d$

$\sin 	heta=\frac{d}{2 d} \Rightarrow \sin 	heta=\fra

Vedclass · Accepted Answer

$\frac{{qvB}}{m}{\mkern 1mu} \left( {\frac{1}{2}\hat j - \frac{{\sqrt 3 }}{2}\hat i} \right)$

Vedclass · Answer

$\overrightarrow{\mathrm{B}}=\mathrm{B} \hat{\mathrm{k}}$

$r=\frac{m v}{q B}$

$r=2 d$

$\sin 	heta=\frac{d}{2 d} \Rightarrow \sin 	heta=\frac{1}{2} \Rightarrow 	heta=\frac{\pi}{6}$

$\vec{a}=\frac{|q| v b}{m}(\cos 	heta(-\hat{i})+\sin 	heta \hat{j})$

$\vec{a}=\frac{|q| v b}{m}\left(-\frac{\sqrt{3}}{2} i+\frac{1}{2} \hat{j}ight)$

The region between $y = 0$ and $y = d$ contains a magnetic field $\vec B = B\hat z$ A particle of mass $m$ and charge $q$ enters the region with a velocity $\vec v = v\hat i$. If $d = \frac{{mv}}{{2qB}}$ , the acceleration of the charged particle at the point of its emergence at the other side is

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