The refractive index of the material of the p | vedclass

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(B) The dispersive power $(\omega)$ of a prism is defined as the ratio of the angular dispersion to the mean deviation.It is given by the formula: $\o

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$0.06$

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(B) The dispersive power $(\omega)$ of a prism is defined as the ratio of the angular dispersion to the mean deviation.It is given by the formula: $\omega = \frac{\mu_v - \mu_r}{\mu_y - 1}$Where:$\mu_v = 1.69$ (refractive index for violet colour)$\mu_r = 1.65$ (refractive index for red colour)$\mu_y = 1.66$ (refractive index for mean colour)Substituting the values into the formula:$\omega = \frac{1.69 - 1.65}{1.66 - 1}$$\omega = \frac{0.04}{0.66}$$\omega = \frac{4}{66} = \frac{2}{33} \approx 0.0606$Rounding to two decimal places,we get $\omega = 0.06$.

The refractive index of the material of the prism for violet colour is $1.69$ and that for red is $1.65$. If the refractive index for the mean colour is $1.66$,calculate the dispersive power of the material of the prism.

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