The refractive index of a material of a prism | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The critical angle $i_c$ for the prism material is given by $\sin(i_c) = \frac{1}{\mu} = \frac{1}{1.5} = \frac{2}{3} \approx 0.667$.Since $\sin(45

Vedclass · Accepted Answer

Vedclass · Answer

(A) The critical angle $i_c$ for the prism material is given by $\sin(i_c) = \frac{1}{\mu} = \frac{1}{1.5} = \frac{2}{3} \approx 0.667$.Since $\sin(45^o) = \frac{1}{\sqrt{2}} \approx 0.707$,we have $\sin(45^o) > \sin(i_c)$,which implies $45^o > i_c$.When a light ray is incident normally on the hypotenuse $BC$,it enters the prism without deviation and strikes the face $AB$ at an angle of incidence of $45^o$.Since the angle of incidence $45^o$ is greater than the critical angle $i_c$,the ray undergoes Total Internal Reflection $(TIR)$ at face $AB$.After reflection,the ray travels parallel to the base $BC$ and strikes the face $AC$ at an angle of incidence of $45^o$.Again,since $45^o > i_c$,the ray undergoes $TIR$ at face $AC$ and emerges normally from the hypotenuse $BC$.This path corresponds to the diagram shown in option $A$.

The refractive index of a material of a prism of angles $45^o -45^o -90^o$ is $1.5$. The path of the ray of light incident normally on the hypotenuse side is shown in

Similar Questions

$A$ plot between the angle of deviation and angle of incidence is shown in the figure. From the graph,one can say that the prism angle is ....... (in $^{\circ}$)

The exit surface of a prism with refractive index $n$ is coated with a material having refractive index $\frac{n}{2}$. When this prism is set for minimum angle of deviation,it exactly meets the condition of the critical angle. The prism angle is . . . . . . (in $^{\circ}$)

The angle of a prism is $5^o$ and its refractive indices for red and violet colors are $1.5$ and $1.6$ respectively. The angular dispersion produced by the prism is ......$^o$.

The angle of a prism is $60^o$ and its refractive index is $\sqrt{2}$. The angle of minimum deviation suffered by a ray of light in passing through it is......$^o$

Vedclass Test Series

Exam Paper Generator

Online Exam Module