The reciprocal of $x+\frac{1}{x}$ is
- A$x-\frac{1}{x}$
- B$\frac{1}{x}+x$
- C$\frac{x}{x^{2}+1}$
- D$\frac{x}{x+1}$
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Similar Questions
Solve the given two equations and select the correct answer from the given options.
$I.$ $x - \sqrt{169} = 0$
$II.$ $y^2 - 169 = 0$
$I.$ $x - \sqrt{169} = 0$
$II.$ $y^2 - 169 = 0$
Easy
View SolutionIf the roots of the equation $ax^2 + bx + c = 0$ are reciprocal to each other,then:
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View SolutionThe equation whose roots are reciprocal of the roots of the equation $3x^2 - 20x + 17 = 0$ is
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View SolutionFind the value of $\frac{(a-b)^{2}}{(b-c)(c-a)}+\frac{(b-c)^{2}}{(a-b)(c-a)}+\frac{(a-c)^{2}}{(a-b)(b-c)}$
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View SolutionIf $x+\frac{1}{y}=1$ and $y+\frac{1}{z}=1$,then find the value of $z+\frac{1}{x}$.
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