The real valued function f(x) = frac{|x-a|}{x | vedclass

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(C) The function is defined as $f(x) = \frac{|x-a|}{x-a}$.Using the definition of the absolute value function,we have:$f(x) = \begin{cases} 1, & 	ext

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a constant function when $x > a$

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(C) The function is defined as $f(x) = \frac{|x-a|}{x-a}$.Using the definition of the absolute value function,we have:$f(x) = \begin{cases} 1, & 	ext{if } x > a \ -1, & 	ext{if } x At $x = a$,the function is undefined because the denominator becomes zero.Since the left-hand limit $\lim_{x 	o a^-} f(x) = -1$ and the right-hand limit $\lim_{x 	o a^+} f(x) = 1$ are not equal,the limit does not exist at $x = a$.For $x > a$,$f(x) = 1$,which is a constant function.Thus,the correct statement is that it is a constant function when $x > a$.

The real valued function $f(x) = \frac{|x-a|}{x-a}$ is

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