The reading of the ammeter in the adjoining f | vedclass

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Question

(C) In the given circuit, the resistors $6\, \Omega, 3\, \Omega$, and $2\, \Omega$ are connected in parallel.
Their equivalent resistance $R_p$ is gi

Vedclass · Accepted Answer

$0.4$

Vedclass · Answer

(C) In the given circuit, the resistors $6\, \Omega, 3\, \Omega$, and $2\, \Omega$ are connected in parallel.
Their equivalent resistance $R_p$ is given by:
$\frac{1}{R_p} = \frac{1}{6} + \frac{1}{3} + \frac{1}{2} = \frac{1 + 2 + 3}{6} = \frac{6}{6} = 1\, \Omega$.
Now, this equivalent resistance $R_p = 1\, \Omega$ is in series with the internal resistor of $4\, \Omega$ and the battery of $2\, V$.
The total resistance of the circuit is $R_{total} = R_p + 4\, \Omega = 1\, \Omega + 4\, \Omega = 5\, \Omega$.
The current $I$ flowing through the circuit is given by Ohm's law:
$I = \frac{V}{R_{total}} = \frac{2\, V}{5\, \Omega} = 0.4\, A$.
Thus, the reading of the ammeter is $0.4\, A$.

The reading of the ammeter in the adjoining figure will be .............. $A$.

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