The reactivity of compound Z with different h | vedclass

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(A) The $-OH$ group is strongly activating and $o, p$-directing due to its powerful $+M$ effect.$1$. The tert-butyl group $(-C(CH_3)_3)$ is a bulky gr

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$A, B, C$

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(A) The $-OH$ group is strongly activating and $o, p$-directing due to its powerful $+M$ effect.$1$. The tert-butyl group $(-C(CH_3)_3)$ is a bulky group,which creates significant steric hindrance at the ortho position $(B)$ relative to it.$2$. The halogen electrophile $(X^{\oplus})$ size increases in the order $Cl^{\oplus} $3$. With $I_2$,the electrophile is very large,so it only substitutes at the least hindered position $(A)$.$4$. With $Br_2$,the electrophile is smaller,allowing substitution at $A$ and $C$.$5$. With $Cl_2$,the electrophile is the smallest,allowing substitution at all three positions $(A, B, C)$.Thus,the pattern is explained by the steric effect of the halogen $(A)$,the steric effect of the tert-butyl group $(B)$,and the electronic effect of the phenolic group $(C)$ which activates the ring. The correct combination is $A, B, C$.

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