Among the following four compounds:(i) Phenol | vedclass

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(A) The acidity of phenols is determined by the stability of the phenoxide ion formed after the loss of a proton.Electron-withdrawing groups $(EWG)$,s

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$(iv) > (iii) > (i) > (ii)$

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(A) The acidity of phenols is determined by the stability of the phenoxide ion formed after the loss of a proton.Electron-withdrawing groups $(EWG)$,such as $-NO_2$,stabilize the phenoxide ion through $-I$ and $-M$ effects,thereby increasing the acidity.Electron-releasing groups $(ERG)$,such as $-CH_3$,destabilize the phenoxide ion through $+I$ and $+H$ effects,thereby decreasing the acidity.Comparing the compounds:$1$. $(iv)$ Para-nitrophenol: $-NO_2$ at para position exerts both $-I$ and $-M$ effects,providing maximum stabilization.$2$. $(iii)$ Meta-nitrophenol: $-NO_2$ at meta position exerts only $-I$ effect,providing less stabilization than para.$3$. $(i)$ Phenol: Reference compound.$4$. $(ii)$ Methyl phenol: $-CH_3$ group exerts $+I$ and $+H$ effects,destabilizing the phenoxide ion.Thus,the correct order of acidity is $(iv) > (iii) > (i) > (ii)$.

Among the following four compounds:
$(i)$ Phenol
$(ii)$ Methyl phenol
$(iii)$ Meta-nitrophenol
$(iv)$ Para-nitrophenol
The acidity order is:

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Choose the correct answer from the options given below:

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Among the following four compounds:$(i)$ Phenol$(ii)$ Methyl phenol$(iii)$ Meta-nitrophenol$(iv)$ Para-nitrophenolThe acidity order is: