The reaction sequence is as follows:Benzene + | vedclass

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Question

(B) $1$. The reaction of benzene with $CH_3Cl$ in the presence of anhydrous $AlCl_3$ is a Friedel-Crafts alkylation,yielding toluene $(A)$.$2$. The ox

Vedclass · Accepted Answer

It gives test with Fehling's solution

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(B) $1$. The reaction of benzene with $CH_3Cl$ in the presence of anhydrous $AlCl_3$ is a Friedel-Crafts alkylation,yielding toluene $(A)$.$2$. The oxidation of toluene with $CrO_3$ in the presence of acetic anhydride followed by hydrolysis is the Etard reaction,which yields benzaldehyde $(B)$.$3$. Benzaldehyde $(B)$ is an aromatic aldehyde.$4$. Aromatic aldehydes give a positive Tollens' reagent test.$5$. Aromatic aldehydes do not give the Fehling's solution test.$6$. Benzaldehyde does not contain an $\alpha$-methyl group,so it does not give the iodoform test $(NaOH + I_2)$.$7$. Benzaldehyde undergoes the Cannizzaro reaction with concentrated $NaOH$ to form benzoic acid and benzyl alcohol.$8$. Therefore,the statement that it gives a test with Fehling's solution is incorrect.

The reaction sequence is as follows:
Benzene + $CH_3Cl$ $\xrightarrow{Anhy. AlCl_3} A$ $\xrightarrow[(2) H_3O^+, \Delta]{(1) CrO_3 / (CH_3CO)_2O, 273-283K} B$
The incorrect statement about '$B$' is:

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The reaction sequence is as follows:Benzene + $CH_3Cl$ $\xrightarrow{Anhy. AlCl_3} A$ $\xrightarrow[(2) H_3O^+, \Delta]{(1) CrO_3 / (CH_3CO)_2O, 273-283K} B$The incorrect statement about '$B$' is: