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(A) The reaction sequence is as follows:$1$. The conversion of $Toluene$ to $Benzaldehyde$ is an oxidation reaction known as $Etard's$ reaction,which

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$(i) \ CrO_2Cl_2/CS_2, (ii) \ H_3O^+$; $Y = m-nitrobenzaldehyde$

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(A) The reaction sequence is as follows:$1$. The conversion of $Toluene$ to $Benzaldehyde$ is an oxidation reaction known as $Etard's$ reaction,which uses $CrO_2Cl_2$ in $CS_2$ followed by hydrolysis $(H_3O^+)$. Thus,$X = (i) \ CrO_2Cl_2/CS_2, (ii) \ H_3O^+$.$2$. $Benzaldehyde$ contains a $-CHO$ group,which is a deactivating and $meta$-directing group for electrophilic substitution reactions.$3$. Nitration of $Benzaldehyde$ using a nitrating mixture $(HNO_3 + H_2SO_4)$ at $273-283 \ K$ yields $m-nitrobenzaldehyde$ as the major product. Thus,$Y = m-nitrobenzaldehyde$.

What are $X$ and $Y$ in the following reaction sequence?
$Toluene$ $\xrightarrow{X} Benzaldehyde$ $\xrightarrow{HNO_3 + H_2SO_4, 273-283 \ K} Y$

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What are $X$ and $Y$ in the following reaction sequence?$Toluene$ $\xrightarrow{X} Benzaldehyde$ $\xrightarrow{HNO_3 + H_2SO_4, 273-283 \ K} Y$