The reaction of formation of phosgene from CO | vedclass

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Question

Rate $=\mathrm{k}_{\mathrm{5}}[\mathrm{COCl}]^{1}\left[\mathrm{Cl}_{2}ight]^{1}$ (show step)

$\frac{{{{	ext{k}}_3}}}{{{{	ext{k}}_4}}} = \frac{{

Vedclass · Accepted Answer

$r = \,{k_5}\, 	imes \,\frac{{{k_3}}}{{{k_4}}}\, 	imes \,{\left( {\frac{{{k_1}}}{{{k_2}}}} ight)^{1/2}}[CO]{[C{l_2}]^{3/2}}$

Vedclass · Answer

Rate $=\mathrm{k}_{\mathrm{5}}[\mathrm{COCl}]^{1}\left[\mathrm{Cl}_{2}ight]^{1}$ (show step)

$\frac{{{{	ext{k}}_3}}}{{{{	ext{k}}_4}}} = \frac{{[{	ext{COCl}}]}}{{[{	ext{Cl}}][{	ext{CO}}]}} \Rightarrow $ $[{	ext{COCl}}] = \frac{{{{	ext{k}}_3}}}{{{{	ext{k}}_4}}}[{	ext{Cl}}][{	ext{CO}}]$

$\frac{{{{	ext{k}}_1}}}{{{{	ext{k}}_2}}} = \frac{{{{[{	ext{Cl}}]}^2}}}{{\left[ {{	ext{C}}{{	ext{l}}_2}} ight]}} \Rightarrow $ $[{	ext{Cl}}] = {\left( {\frac{{{{	ext{k}}_1}}}{{{{	ext{k}}_2}}}} ight)^{1/2}}{\left[ {{	ext{C}}{{	ext{l}}_2}} ight]^{1/2}}$

Rate $=\mathrm{k}_{5} 	imes \frac{\mathrm{k}_{3}}{\mathrm{k}_{4}} 	imes[\mathrm{Cl}][\mathrm{CO}]\left[\mathrm{Cl}_{2}ight]^{1}$

Rate $=\mathrm{k}_{5} 	imes\left(\frac{\mathrm{k}_{1}}{\mathrm{k}_{2}}ight)^{1 / 2}\left[\mathrm{C}_{2}ight]^{1 / 2}[\mathrm{CO}]\left[\mathrm{Cl}_{2}ight]^{1}$

$=\mathrm{k}_{\mathrm{5}} 	imes \frac{\mathrm{k}_{3}}{\mathrm{k}_{4}} 	imes\left(\frac{\mathrm{k}_{1}}{\mathrm{k}_{2}}ight)^{1 / 2} 	imes[\mathrm{CO}]^{1}$ ${\left[ {{	ext{C}}{{	ext{l}}_2}} ight]^{3/2}}$

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