The reaction of ethyl methyl ketone with Cl_2 | vedclass

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Question

(B) Ethyl methyl ketone is $CH_3CH_2COCH_3$. It contains a methyl ketone group $(-COCH_3)$,which undergoes the haloform reaction in the presence of $C

Vedclass · Accepted Answer

$CH_3CH_2COCCl_3$

Vedclass · Answer

(B) Ethyl methyl ketone is $CH_3CH_2COCH_3$. It contains a methyl ketone group $(-COCH_3)$,which undergoes the haloform reaction in the presence of $Cl_2$ and excess $OH^-$. The methyl group $(-CH_3)$ is converted into a chloroform group $(-CCl_3)$ through successive halogenation and cleavage steps. The final product formed is $CH_3CH_2COCCl_3$ ($1$,$1$,$1$-trichlorobutan$-2-$one). Therefore,the correct option is $B$.

The reaction of ethyl methyl ketone with $Cl_2$ in the presence of excess $OH^-$ gives the following major product:

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